Processing math: 100%
105-2第三次段考sim
(y-4)^2=16(x-2)
V(2,4)
F(6,4)
L:x=-2
(x-2)^2=16(y-4)
V(2,4)
F(2,8)
L:y=0
\displaystyle{\frac{(x-2)^2}{25}+\frac{(y-4)^2}{9}=1}
O(2,4)
a=5
b=3
c=4
\displaystyle{\frac{(y-4)^2}{25}+\frac{(x-2)^2}{9}=1}
O(2,4)
a=5
b=3
c=4
\displaystyle{\frac{(x-2)^2}{16}-\frac{(y-4)^2}{9}=1}
O(2,4)
a=4
b=3
c=5
L_1:3x+4y=22
L_2:3x-4y=-10
\displaystyle{\frac{(y-4)^2}{16}+\frac{(x-2)^2}{9}=1}
O(2,4)
a=4
b=3
c=5
L_1:4x-3y=-4
L_2:4x+3y=20